Convert The Following Expression To The Indicated Base

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Introduction

Converting a numeric expression from one base to another is a fundamental skill in computer science, digital electronics, and mathematics. That said, this article walks you through the entire conversion process, explains the underlying theory, and provides step‑by‑step examples for the most common bases: binary (base 2), octal (base 8), decimal (base 10), and hexadecimal (base 16). Whether you are decoding a binary instruction set, working with hexadecimal color codes, or simply checking a calculator’s output, the ability to convert the following expression to the indicated base empowers you to interpret data correctly and avoid costly mistakes. By the end, you will be able to handle any conversion request confidently, from simple integers to complex mixed‑radix expressions.

Why Base Conversion Matters

  1. Computer architecture – CPUs operate natively in binary; memory addresses are often expressed in hexadecimal for compactness.
  2. Networking – IPv6 addresses use hexadecimal, while subnet masks may be shown in binary.
  3. Programming – Low‑level languages (C, assembly) require literals in different bases for bit‑masking and flag manipulation.
  4. Education – Understanding base systems reinforces concepts of place value, modular arithmetic, and number theory.

Because these domains intersect, a systematic conversion method is essential for both students and professionals.

Core Concepts

Place Value in Any Base

A number in base b is expressed as

[ N = d_{n-1}b^{n-1}+d_{n-2}b^{n-2}+ \dots + d_{1}b^{1}+d_{0}b^{0} ]

where each digit (d_i) satisfies (0 \le d_i < b). The rightmost digit has weight (b^{0}=1); moving left multiplies the weight by b each step Simple, but easy to overlook..

Two Main Conversion Strategies

Strategy When to Use Steps
Direct (positional) conversion Small numbers, or when the source and target bases are powers of each other (e.g., binary ↔ octal, binary ↔ hexadecimal) Group digits, replace each group with its equivalent digit in the target base.
Intermediate decimal conversion Arbitrary bases, large numbers, or mixed‑radix expressions 1️⃣ Convert source number → decimal. 2️⃣ Convert decimal → target base.

Both strategies rely on repeated division or multiplication, which we will illustrate in detail.

Step‑by‑Step Procedure

1. Identify the Source Expression and Target Base

Example: Convert the binary expression 101101₂ to hexadecimal (base 16).

2. Choose the Appropriate Strategy

Since 2 and 16 are powers of each other (16 = 2⁴), direct conversion is fastest Worth keeping that in mind..

3. Apply Direct Conversion (Power‑of‑Two Bases)

  1. Pad the binary number on the left with zeros so its length is a multiple of 4 (because 16 = 2⁴).
    • 101101 → 0010 1101 (8 bits).
  2. Group the bits into 4‑bit blocks: 0010 and 1101.
  3. Translate each block to its hexadecimal digit:
    • 0010₂ = 2₁₆
    • 1101₂ = D₁₆
  4. Combine the digits: 2D₁₆.

Result: 101101₂ = 2D₁₆.

4. Apply Intermediate Decimal Conversion (General Case)

Suppose we must convert 7A3₁₆ (hex) to octal (base 8).

  1. Hex → Decimal

    • Expand using place values:
      [ 7A3_{16}=7\cdot16^{2}+A\cdot16^{1}+3\cdot16^{0} ]
    • Remember A = 10.
    • Compute:
      [ 7\cdot256 = 1792,\quad 10\cdot16 = 160,\quad 3\cdot1 = 3 ]
    • Sum: 1792 + 160 + 3 = 1955₁₀.
  2. Decimal → Octal (repeated division by 8)

Quotient Remainder
1955 ÷ 8 = 244 3
244 ÷ 8 = 30 4
30 ÷ 8 = 3 6
3 ÷ 8 = 0 3

Reading remainders bottom‑up gives 3643₈.

Result: 7A3₁₆ = 3643₈ And that's really what it comes down to..

5. Converting Fractions

Fractional parts require multiplication rather than division.

Convert 0.101₂ to decimal:

Step Multiply by 2 Integer part New fractional part
1 0.101 × 2 = 1.010 1 0.010
2 0.On the flip side, 010 × 2 = 0. Plus, 100 0 0. Now, 100
3 0. 100 × 2 = 0.200 0 0.200
4 0.Now, 200 × 2 = 0. 400 0 0.

The integer parts collected (1000…) represent the decimal fraction 0.625.

To convert a decimal fraction to binary, repeat multiplication by 2, recording the integer part each time, until the fraction becomes 0 or a desired precision is reached.

Detailed Examples

Example 1 – Binary to Decimal (Integer)

Convert 1101101₂ to decimal.

[ \begin{aligned} 1\cdot2^{6} &= 64 \ 1\cdot2^{5} &= 32 \ 0\cdot2^{4} &= 0 \ 1\cdot2^{3} &= 8 \ 1\cdot2^{2} &= 4 \ 0\cdot2^{1} &= 0 \ 1\cdot2^{0} &= 1 \ \text{Total} &= 64+32+8+4+1 = 109_{10} \end{aligned} ]

Result: 1101101₂ = 109₁₀ And that's really what it comes down to..

Example 2 – Decimal to Hexadecimal (Integer)

Convert 254₁₀ to hexadecimal.

  1. 254 ÷ 16 = 15 remainder 14 → digit E.
  2. 15 ÷ 16 = 0 remainder 15 → digit F.

Reading remainders upward: FE₁₆.

Result: 254₁₀ = FE₁₆ Easy to understand, harder to ignore..

Example 3 – Octal to Binary (Direct)

Convert 745₈ to binary.

Octal digit Binary equivalent (3 bits)
7 111
4 100
5 101

Combine: 111 100 101₂.

Result: 745₈ = 111100101₂ Worth knowing..

Example 4 – Hexadecimal to Binary (Direct)

Convert 3B9₁₆ to binary.

Hex digit Binary (4 bits)
3 0011
B (11) 1011
9 1001

Combined: 0011 1011 1001₂.

Result: 3B9₁₆ = 001110111001₂ Easy to understand, harder to ignore..

Example 5 – Binary Fraction to Hexadecimal

Convert 0.11011₂ to hexadecimal That alone is useful..

  1. Pad to groups of 4 bits: 0.1101 1000 (add three trailing zeros).
  2. Group: 1101 → D, 1000 → 8.

Result: 0.11011₂ = 0.D8₁₆ Not complicated — just consistent..

Example 6 – Converting a Mixed Expression

Convert the expression

[ (1011_2 + 27_{10}) \times 3_8 ]

to decimal, then to hexadecimal.

Step A – Convert each operand to decimal

  • 1011₂ = 1·2³ + 0·2² + 1·2¹ + 1·2⁰ = 8 + 0 + 2 + 1 = 11₁₀.
  • 27₁₀ is already decimal.
  • 3₈ = 3·8⁰ = 3₁₀.

Step B – Perform arithmetic in decimal

[ (11 + 27) \times 3 = 38 \times 3 = 114_{10} ]

Step C – Decimal → Hexadecimal

  1. 114 ÷ 16 = 7 remainder 2 → digit 2.
  2. 7 ÷ 16 = 0 remainder 7 → digit 7.

Result: 114₁₀ = 72₁₆.

Thus the original expression evaluates to 72₁₆.

Frequently Asked Questions

Q1. Can I convert directly between any two bases?

A: Direct conversion works smoothly when the bases are powers of each other (2↔4↔8↔16). For unrelated bases (e.g., base 5 to base 12), use the intermediate decimal method.

Q2. What if the number is very large?

A: Break the number into manageable blocks. For binary→hex, group every four bits; for binary→octal, group every three bits. For decimal→other bases, perform repeated division using a calculator or a script.

Q3. How many fractional digits should I keep?

A: Fractions often become repeating in another base. Decide on a precision (e.g., 4‑6 digits) that satisfies your application. In engineering, 8‑12 bits after the binary point are typical That alone is useful..

Q4. Why do some conversions produce repeating patterns?

A: A fraction terminates in base b only if its denominator (in lowest terms) contains prime factors that are also factors of b. To give you an idea, 1/3 terminates in base 3 (0.1₃) but repeats in decimal (0.333…₁₀) Turns out it matters..

Q5. Is there a quick mental trick for small numbers?

A: Memorize the first 16 decimal‑hex equivalents and the 8 binary‑octal equivalents. With these, you can instantly translate single‑digit values without calculation.

Tips for Mastery

  • Write down the place values before expanding; it prevents sign errors.
  • Always verify by converting back to the original base.
  • Use tables for common digit groups:
Binary (4 bits) Hex
0000 0
0001 1
… …
1111 F
  • Practice with real‑world data: color codes (#FF5733), IP addresses (192.168.0.1), or assembly opcodes.
  • Automate repetitive conversions with simple scripts (Python’s int() and format() functions are handy).

Conclusion

Converting the following expression to the indicated base is more than a rote exercise; it reinforces the universal language of numbers across different numeral systems. Which means by mastering direct grouping for power‑of‑two bases and the intermediate decimal method for arbitrary bases, you gain the flexibility to tackle any conversion—whether it involves whole numbers, fractions, or complex arithmetic expressions. Worth adding: apply the step‑by‑step procedures, keep the handy digit tables nearby, and verify your results by reversing the conversion. With practice, these techniques become second nature, empowering you to read binary machine code, write clean hexadecimal literals, and decode octal permissions with confidence.

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